Berkut666 wrote:
So maths is not my strong point (nearly 40 years on this planet and in all honest I am still not sure what it!) but in your equation above would that not mean that if you were playing an opponent with a far greater number of activation's than you the cost for the "naked activation" would be higher?? Which doesn't seem right. Surely if they have way more units than you, the cost should be less?
50 + 10 x 2 = 70
50 + 10 x 5 + 100
or change it to 50 + 100/ N? again where N is the difference between you and your opponents activations?
50 + 100/2 = 100
50+ 100/5 = 70
No, N is the ‘difference’ (in American English that means the resulting value after one number is subtracted from another) between the number of activations in each army.
In your example, where a player with 2 activations is playing against a player with 5 activations, N = 2 - 5 = -3
That gives the following value of an naked activation for the player with fewer activations:
50 + 10N = 50 -30 = 20
I don’t actually think that the correct equation, I was just throwing it out there as an example.